Graphical Representation of Motion

The velocity-time graph of the particle moving along a straight line is shown. The rate of acceleration and deceleration is constant and it is equal to $5 \mathrm{m} {\mathrm{s}}^{-2}$. If average velocity during the motion is $20 \mathrm{m} {\mathrm{s}}^{-1}$, then find the value of $t$

The shape of a distance-time graph for constant accelerated motion moving in a single direction is

A ball is dropped from a certain height on the surface of the glass. It collides elastically and comes back to the initial position. If this process is repeated then the velocity-time graph is:-

A ball is dropped from some height. After rebounding from the floor it ascends to the same height. Draw the velocity-time graph for the given motion.

A batsman hits a sixer and the ball touches the ground outside the cricket ground. Among the following graph, the one that describes the variation of the cricket ball's vertical velocity $\mathrm{v}$ with time between the time ${\mathrm{t}}_1$ as it hits the bat and time ${\mathrm{t}}_2$ when it touches the ground is

If the height can be expressed as $\mathrm{h}=(12{\mathrm{t}}^2+4\mathrm{t}) \mathrm{m}$, the value of $\mathrm{h}$after $\mathrm{t}=1 \mathrm{s}$ is

In projectile motion, the height of the object varies with respect to time.

The speed of a train increases at a constant rate $\alpha$ from zero to $v$ and then remains constant for an interval and finally decreases to zero at a constant rate $\beta$. The total distance travelled by the train is $l$. The time taken to complete the journey is $t$. Then, 

The fig. shows the v-t graph of a particle moving in straight line. Find the time (in seconds) when particle returns to the starting point.

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For given $V-t$ graph find out displacement from $t=0$ to $t=5$ second

The acceleration -time graph of a body is shown below.

The most probable velocity-time graph of the body is

The velocity - time graph of a body is shown in figure. The ratio of the ...during the intervals OA and AB is ....

A rocket is fired upwards. Its fuel exhausts fully in 12 seconds. The height reached by the rocket as calculated from its velocity-time graph is

The velocity-time graph of a particle moving along a straight line is shown in the figure. The displacement of the body in $5 \mathrm{s}$ is

The displacement-time graphs of two particles $A$ and $B$ are straight lines making angles of respectively $30°$ and $60°$ with the time axis. If the velocity of $A$ is $v_A$ and that of $B$ is $v_B$, then the value of $\frac{v_A}{v_B}$ is

The variation of velocity of a particle moving along a straight line is shown in the figure. The distance travelled by the particle in $4 s$  is

The velocity-time graph of a particle moving along a straight line is as shown in diagram. The rate of acceleration and retardation is constant and is equal to $5 \mathrm{m} {\mathrm{s}}^{-2}$. If the average velocity during the motion is $20 \mathrm{m} {\mathrm{s}}^{-1}$, then
  
The distance travelled with uniform velocity is

shows the velocity (v) of a particle plotted against time (t).

Initially car $A$ is $10.5 \mathrm{m}$ahead of car $B$. Both start moving at time $t = 0$ in the same direction along a straight line. The velocity time graph of two cars is shown in figure. The time when the car $B$ will catch the car $A$, will be ;

Two trains, which are moving along different tracks in opposite directions, are put on the same track due to a mistake. Their drivers, on noticing the mistake, start slowing down the trains when they are 300 m apart. Graphs given below show their velocities as a function of time as they slow down. The separation between the trains, when both have stopped, is :